Opening a form based on the result of a MsgBox

28 May 2005 3:10 PM

PM

After users click on a button on a main form, they are presented with a
question. If they answer 'Yes', the next form is to open with records
visible for them to choose from. If they answer 'No', the same form is to
open with no records to choose from. It should allow them to create a new
record in the database.

The command button of the main form has an If .. Then statement. Right now,
only the If part of it has code. The code is

If response = MsgBoxResult.Yes Then
Dim frmUserInformation As New frmUserInformation
frmUsertInformation.ShowDialog()

The Form_Load procedure of the user information form has the code to load
the User information from the database.

I want to be able to load the new form based on what the user clicks in the
dialog box. The new form will either allow them to choose a record, or allow
them to create a new one.

Please help. I am new to VB. I appreciate it.

P

28 May 2005 3:26 PM

Bob Butler

"PM" <P*@discussions.microsoft.com> wrote in message news:8F61688F-03C8-

4BB4-9C9C-D70BCE6BF***@microsoft.com
Show quoteHide quote

> After users click on a button on a main form, they are presented with
> a question. If they answer 'Yes', the next form is to open with
> records visible for them to choose from. If they answer 'No', the
> same form is to open with no records to choose from. It should allow
> them to create a new record in the database.
>
> The command button of the main form has an If .. Then statement.
> Right now, only the If part of it has code. The code is
>
> If response = MsgBoxResult.Yes Then
> Dim frmUserInformation As New frmUserInformation
> frmUsertInformation.ShowDialog()

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