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Scroll a node into view -- ASPNET 2.0 TreeviewAnybody figure this out? I can't figure out how to get the node's client
side control ID in order to grab aholt of it. I've seen a post that says that the node's ID is: TreeView.ID + (index of the TreeNode in TreeView.Nodes collection). The problem is that, even after a postback, you can't get the index of the treenode in the collection. You'd think that this would work: (after SelectedNodeChanged postback) TreeView.Nodes.IndexOf(TreeView.SelectedNode) --or-- (when you have the ValuePath) TreeView.Nodes.IndexOf(TreeView.FindNode(ValuePath)) Both of which return -1 for the node index. So what's the solution? Placing the solution here for future reference:
The TreeView creates an object in Javascript on the client side that's called [treeview name]_Data i.e., if the treeview is named tvNavigation, the object's name would be tvNavigation_Data This object has a property called selectedNodeID. This property has a ... property called value that contains the id of the currently selected node. So var name = tvNavigation_Data.selectedNodeID.value; var selectedNode = Document.all?Document.all[name]:Document.getElementById(name); if(selectedNode){ selectedNode.scrollIntoView(true); } will scroll the currently selected node into view. Show quoteHide quote "William Sullivan" wrote: > Anybody figure this out? I can't figure out how to get the node's client > side control ID in order to grab aholt of it. I've seen a post that says > that the node's ID is: TreeView.ID + (index of the TreeNode in > TreeView.Nodes collection). The problem is that, even after a postback, you > can't get the index of the treenode in the collection. You'd think that this > would work: > (after SelectedNodeChanged postback) > TreeView.Nodes.IndexOf(TreeView.SelectedNode) > --or-- > (when you have the ValuePath) > TreeView.Nodes.IndexOf(TreeView.FindNode(ValuePath)) > > Both of which return -1 for the node index. So what's the solution? > The TreeView creates an object in Javascript on the client side that's called
[treeview name]_Data i.e., if the treeview is named tvNavigation, the object's name would be tvNavigation_Data This object has a property called selectedNodeID. This property has a ... property called value that contains the id of the currently selected node. So var name = tvNavigation_Data.selectedNodeID.value; var selectedNode = Document.all?Document.all[name]:Document.getElementById(name); if(selectedNode){ selectedNode.scrollIntoView(true); } will scroll the currently selected node into view. Show quoteHide quote "William Sullivan" wrote: > Anybody figure this out? I can't figure out how to get the node's client > side control ID in order to grab aholt of it. I've seen a post that says > that the node's ID is: TreeView.ID + (index of the TreeNode in > TreeView.Nodes collection). The problem is that, even after a postback, you > can't get the index of the treenode in the collection. You'd think that this > would work: > (after SelectedNodeChanged postback) > TreeView.Nodes.IndexOf(TreeView.SelectedNode) > --or-- > (when you have the ValuePath) > TreeView.Nodes.IndexOf(TreeView.FindNode(ValuePath)) > > Both of which return -1 for the node index. So what's the solution? > 
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